Came across this problem the other day and it’s been bugging me. Imagine you’re flipping a fair coin until you get two heads in a row. What’s the expected number of flips you’d need to make that happen? At first glance, it feels like it should be straightforward, but the more I think about it, the twistier it gets. Anyone have a good way to approach this? I’ve tried drawing out the possible sequences, but I’m not sure if I’m overcomplicating it. Would love to hear how others would tackle it maybe there’s an elegant solution I’m missing!
This is a classic probability problem with a clear mathematical solution. The expected number of flips is 6 we can model this using states and recurrence relations. The key insight is recognizing the different possible states between consecutive heads.
Oh wow, math is so tricky! I don’t really get all those big words, but 6 flips sounds like a lot to me. Are you sure it’s not just luck?
Math is just witchcraft with numbers, honestly. Six flips? That’s basically a coin acrobatics show! Luck’s probably backstage taking a nap.